Friday, September 30, 2011


Navodaya Vidyalaya Samiti (NVS), an autonomous organization under the Ministry of Human Resource Development, Department of School Education & Literacy, Government of India, invites applications in the prescribed format (Annexure-I), from eligible Indian nationals for filling up of vacancies and drawing a panel of candidates for the posts of Trained Graduate Teachers DIRECT RECRUITMENT BASIS in the Jawahar Navodaya Vidyalayas located in various districts of the country.

Last date for submission of applications is within 30 days from the date of publication of this 

advertisement (advertisement published in Employment News dated 24-30 September, 2011).



UPPER AGE LIMIT : 35 YEARS (As on 30.09.2011)

PAY SCALE: Rs. 9300-34800 (Grade Pay Rs. 
(a) Four years integrated degree course of Regional College of Education of NCERT with at least 50% marks in the concerned subject as well as in the aggregate.
A Bachelor’s Degree or equivalent from a recognized University with 50% marks or above in aggregate as well as in the concerned subject comprising the combination as under:
POST                                                  SUBJECTS

TGT(Hindi)                              Hindi as an Elective Subject at Degree Level

TGT(English)                           English as an Elective Subject at Degree Level

TGT(Maths)                             Maths, Physics and Chemistry

TGT(Social Science)                Any two subjects amongst History/Geography/ Economics/Political        
                                                  Science out of which one must be History/Geography
TGT(Science)                            Botany, Zoology and Chemistry

(b) B.Ed. or equivalent from a recognized University. 

(c) Competence to teach through English and Hindi/Regional language as the case may be.

(d) Qualified Central Teacher Eligibility Test (Paper - II) conducted by CBSE.

Revised Fee for Private Candidates In CBSE Examination - 2012

Candidate who will appearing for the senior school (Class XII) & secondary school (Class X) Examination in March 2012 a here by informed that the examination fee has been revised. 
Schedule of Fee:
Without late Fee: 15-09-2011
With Late Fee of Rs. 150/- : up-to 30-09-2011
With Late Fee of Rs. 250/- : up-to 15-10-2011
With Late Fee of Rs. 350/- : up-to 30-10-2011

Wednesday, September 28, 2011

CBSE I NCERT Chapter -Light _Refraction and Refraction solved Questions

1. Out of convex mirror and concave mirror, whose focus is situated behind the mirror?
Ans: The focus of convex mirror is situated behind it.
2. For what position of an object, a concave mirror forms an enlarged virtual image?
Ans: Object between pole (P) and focus (F) of the concave mirror.
3. If the focal length of a concave mirror is 25cm. What is its radius of curvature?
Ans: Focal length = Radius of curvature / 2
25 = R / 2  => R = 50cm.
4. A ray of light falls on a mirror normally. What are the values of angle of incidence andthe angle of reflection?
Ans: Both angle of incidence and the angle of reflection are zero.
5. What is the focal length of a plane mirror?
Ans: Infinite.
6. Which spherical mirror is called a divergent mirror?
Ans: A convex mirror is called a divergent mirror.
7. What is the angle of incidence, when a ray of light falls on the spherical mirror from itscentre of curvature?
Ans: The angle of incidence is zero, when a ray of light falls on the spherical mirror from its centre of curvature.
8. Name the type of mirror that always forms a virtual image for a real object?
Ans: Convex Mirror.
9. State the relation between radius of curvature and focal length of spherical mirrors.
Ans: Radius of curvature = 2 X focal length.
R = 2f.
10. Which of the two is a diverging lens? Convex lens (or) Concave lens.
Ans: Concave lens.
11. If an object is placed at a distance of 10cm in front of a plane mirror, how far would it be from its image?
Ans: The object would be at a distance of 20cm from its image.
12. Name the physical quantity which remains the same when light goes from one medium to another?Ans: Frequency of light.
13. Define power of a lens.
Ans: The reciprocal of the focal length of the lens is called power of a lens. P = 1/f
14. Calculate the power of a convex lens of focal length 25cm?
Ans: Focal length f = 25cm.
Power = 1/.25 = 100/25 = +4D.
15. Name the phenomenon responsible for the following affect.
When we sit in front of a plane mirror and write with our right hand, it appears in the mirror that we are writing with the left hand.
Ans: Lateral Inversion.
16. Define Refractive Index:
Ans: It is the ratio of speed of light in vacuum to the speed of light in medium is called Refractive index.
17. Why is the convex lens also known as a converging lens?
Ans: A convex lens is also known as a converging lens because it converges a parallel beam of light raying passing through it.
18. Give the ratio of velocities of two light waves travelling is vacuum and having wave lengths 4000A0 and 8000A0.
Ans: In Vacuum, light of all the wave lengths travel with the same velocity i.e. 3 X 108 m/sec.
19. For what angle of incidence, the lateral shift produced by parallel sided glass plate is zero?
Ans: For i = 0.
20. What are the factors on which the lateral shift depends?
Ans: Thickness of the refracting medium, angle of incidence and its refractive index.
21. What is the power of a plane glass plate?
Ans: Zero.
22. An object is placed at the focus of a concave lens. Where will its image be formed?
Ans: The rays will appear to come from infinity. Therefore, a virtual image will be formed at infinity.
23. What is the unit of power of a lens?
Ans: Dioptre.
24. Refractive index of media A,B,C and D are
A 1.54
B 1.33
C 1.46
D 1.62
In which of the four media is the speed of light (i) Minimum (ii) Maximum.
Ans: (i) Speed of light is minimum in medium D (n = 1.62).
(ii) Speed of light is maximum is medium B (n = 1.33).
25. Why the stars appear to twinkle?
Ans: The twinkling of a star is due to the atmospheric refraction of star’s light.
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Tuesday, September 27, 2011

National Level Science Talent Search Examination 2011

National Level Science Talent Search Examination
NSTSE is a diagnostic test which actually helps students improve.
Unlike regular tests which try only to find out how much a child knows (or has memorized), NSTSE measures how well a student has understood concepts and gives detailed feedback on the same, to help them improve.

Thus NSTSE helps each student know whether he/she has actually understood a concept early on so that immediate action can be taken. Often students have conceptual gaps which increase as they progress and when they reach the higher classes, they develop a "phobia" for the subject.

School tests - including board exams - tend to be superficial, testing what children have memorised. But the important skills like the ability to think independently and reason logically - critical in today's world - are often not emphasised in school tests.
The focus on fundamentals is so important that when the child finishes studies he/she will have to face the competitive world armed with these fundamentals. Even while opting for higher studies, the student has to go through a complete scan of what he/she knows and how much. Exams like IIT-JEE, AIEEE, AFMC, AIIMS, GRE, GMAT, CAT etc., are so designed to test the fundamental strength of student. Hence the need of the hour is building the fundamentals base as strong as possible.
This exactly is the philosophy behind the Unified Council's NSTSE.

NSTSE is unlike other tests in many different ways. It

Monday, September 26, 2011

X CBSE | NCERT E- Notes For Ch - Periodic Classification of Elements of Elements

Classification of elements: the arrangement of elements in such a manner that elements with similar properties are grouped together while elements with dissimilar properties are separated.

1. Lavoisier’s classification of elements: In 1789, Lavoisier first attempted to classify the elements into two divisions namely Metals and Non-metals. However this classification was not satisfactory as there were many exceptions in each category.
2. Dobereiner’s classification of elements: In 1817, Johann Wolfgang Dobereiner grouped three elements into what he termed triads.
In each case, the middle element has an atomic mass almost equal to the average atomic masses of the other two elements in the triad.
For example, elements like lithium, sodium and potassium have atomic masses 7, 23 and 39 respectively. They are grouped together into a triad as,
Li (7) Na (23) K (39)
Here the atomic mass of sodium is the average of atomic masses of lithium and potassium.
Limitation of Dobereiner’s law
Only three triads were identified from the element known at that time. Hence, this classification was not useful.
Newland’s law of octaves:              Read more »

Links For   CBSE Class X Science Term-II
For Solved CBSE Exam questions Visit  Read more

Sunday, September 25, 2011

NTSE sample questions for preparation Math science

10th maths Extra score questions chapter Pair of L...

10th maths Extra score questions
Pair of Linear Equation in Two Variable HOTS By JSUNIL TUTORIAL
1 mark questions :-
Q. 1 Is the pair of linear equations consistent: - x + y = 3 ; 3x – 2y = 4 .
Q. 2 Find out whether the lines representing the following pair of linear equations are parallel or coincide:- 6x – 3y +10 = 0 ; 2x – y + 9 = 0
Q. 3 Write the value of k for which the following pair of linear equations has unique solution:-
x + k y + 6 = 0 ; 2x + 3y + 8 = 0
Q. 4 Write the value of k for which the following pair of linear equations has no solution: -
4x +y =11 ; k x + 3y =5
Q. 5 Write the value of k for which the system of equations has infinite solutions:-
2x – 3y +10 = 0 ; 3x – ky +15 = 0
Q. 6 Does (2, –3) lie on the linear equation 3x – 2y + 5 = 0

Saturday, September 24, 2011

Friday, September 23, 2011

CBSE Assessment of Practical Skills in Science class X

Set-1Practical Skills in Science
1. The two colours seen at the extreme ends of the pH chart are
(a) red and blue.  (b) red and green. (c) green and blue. (d) orange and green
Ans: (a) Red colour is at the top and blue colour is at the bottom.
2. A student observed that the colour of pH paper changes to green when shedipped it in water. She added a few drops of concentrated hydrochloric acid to the water. The colour of pH paper would turn to
(a) light red.  (b) apple green. (c) dark blue. (d) lemon yellow.
Ans: (a) The colour of pH paper is green in neutral medium, whereas it is red in acidic medium.
3. When zinc reacts with dilute hydrochloric acid
(a) the surface of zinc becomes brighter.   (b) the surface of zinc becomes black and dull.
(c) the metal turns into powder.                  (d) the reaction mixture turns green.
Ans: (b)  The surface becomes black and dull as the reaction proceeds
4. Students A, B and C were given five raisins each of equal weight. The raisins  were soaked in distilled water at room temperature. A removed the raisins after 20 minutes, B after two hours and C after 40 minutes. If PA, PB and PC denote percentage absorption of water obtained by students A, B and C respectively, then

Thursday, September 22, 2011

Sample Paper – 2012 Class – IX Subject – Mathematics Topic- HERON’S FORMULA

Multiple Choice Questions (5×1)      
Choose the correct answer from the given four options in the following questions:

1. Two sides of a triangle are 8cm and 11cm and its perimeter is 32cm.The third side is :
              (a) 4cm        (b) 13cm          (c) 14cm     (d) 16cm
2. The base of a triangle is 12cm and height is 8cm .Its area is:
             (a) 24cm2    (b) 96cm2        (c) 48cm2     (d) none
3. The sides of a triangular plot are in the ratio 3:5:7 and its perimeter is 300m . The sides of a triangle are.
             (a) 60m,100m,40m   (b) 50m,80m,60m   (c) 45m,75m,95m    (d) none
4. What will be the area of quadrilateral ABCD if AB =3cm, BC=4cm, CD=4cm, DA=5cm and AC=5cm.
             (a) 12.5cm                  (b) 15.2cm            (c) 18.2cm            (d)19.2cm

Wednesday, September 21, 2011

CBSE MATH STUDY: Sample Paper 2011-2012 | First Term | Mathematics|9th

CBSE MATH STUDY: Sample Paper 2011-2012 | First Term | Mathematics| 9th
Q.1Two lines are respectively perpendicular to two parallel lines. Show that they are parallel to each other.
Q.2 Prove that two lines that are respectively perpendicular to two ntersecting lines intersect each other.

Q.3Bisectors of interior ∠B and exterior ∠ACD of a Δ ABC intersect at the point T. Prove that ∠ BTC =1/2 ∠ BAC.
Q.4. BP and CP are bisector of In a triangle AC>AB Prove that (i) PC > PB (ii) BD > PD (iii)DC>PD

Monday, September 19, 2011

MATH ADDA "10TH MATHS BY JSUNIL": 10th maths polynomial extrascore questions

MATH ADDA "10TH MATHS BY JSUNIL": 10th maths polynomial extrascore questions: Math Adda Chapter: POLYNOMIAL YEAR-2011-2012 LEVEL-I 1. The zeroes of the polynomial 2x 2 -3x-2 are a. ...

MATH ADDA 10th Number system solved important question

MATH ADDA "10TH MATHS BY JSUNIL": 10th Number system solved important question: 1. Prove that one of every three consecutive integers is divisible by 3. Ans: n,n+1,n+2 be three consecutive positive integers We k...

HTET 2011(Haryana TET) Exam Date Changed

Haryana Board of secondary education, bhiwani has modified the exam dates of HTET 2011. It is declared that the previously announced dates of HTET examinations as 24 September 2011 and 25 September 2011 has been postponed to the new dates.
As per the circular the new dates are as below :
Category 3 (Lecturer group) : November 5, 2011 (Saturday) from 11:00 am to 12:30 pm.

Category 1 (Primary Teachers) : November 6, 2011 (Sunday) from 11:00 am to 12:30 pm.

Category 2 (Elementary Teachers) : November 6, 2011 (Sunday) from 02:30 pm to 04:00 pm.

All the candidates will get their new admit cards before the exams. You are advised to get in touch with the website for latest updates.

Sunday, September 18, 2011


CBSE SAMPLE PAPER MATHEMATICS (Class-8): CBSE TEST PAPER 8TH MATHEMATICS SA-1 1. What least number must be subtracted from 7250 to get a perfect square? Also, find the square root o...

8th maths question paper

CBSE 8th CHAPTER: Percentage For All class 8th Maths test paper  JSUNIL TUTORIAL
1. Choose the correct answer.

(i) There are 5 oranges in a basket of 25 fruits. The percentage of oranges is ___

(A) 5% (B) 25% (C) 10% (D) 20%

(ii) 2/25 = _______ %.

(A) 25 (B) 4 (C) 8 (D) 15

(iii) 15% of the total number of biscuits in a bottle is 30. The total number of biscuits is _______.

Saturday, September 17, 2011


1. Rainy season comes always after summer season. Why?
2. Wet clothes dry faster if you keep them under a fan. Why?
3. If you won’t drink enough water, what happens to your body?
4. A village near a river will always get ground water where as a
village which is far away will face acute water problem. Why?
5. You are drenched completely while playing in the rain. But you did not stop playing. To your surprise, your clothes dried after some time.How?
1. Sky appears blue. Why?
2. How the fish could live in water?
3. Your father while going to the office, keep a mask to his nose. Did you ever ask your father why he will keep it?
4. Why mountaineers carry Oxygen cylinders with them while climbing high mountains?
5. If you add mud to water, you observe bubbles in water. Why?
1. Each tree can make its own manure. How?
2. You have noticed your mother keeping fruits in plastic bags. Is
it safe to eat them? 3. Rag pickers always suffer with diseases. Why?
4. You covered the soil with a plastic sheet and poured water on it. The soil will not become Wet. Similarly you covered the soil with a sheet of paper and poured water. Soil has become wet. Which helps in increasing the ground water and why?
5. Earthworms increase the fertility of the soil. How?
Motion and Measurement of Distance
1. You are given a cotton thread and a wool thread. Which thread can be used to measure the length of an object and why?
2. You have seen your father playing violin.While playing it, you observed that the strings. Are creating the sound.Can you tell due to what motion it si giving the sound?
3. When a fan is rotating , we observe the blades are rotating in opposite direction. Why?
4. While playing a kite you observe the kite motion will not be in the same direction. Why?
5. Name some objects having periodic motion.
1. In a completely dark room, can you see your face in a mirror? Why?
2. Why can not we see upside down image of the sun?
3. Why shadows are black in colour?
4. Can you an object through a “T” shaper pipe? If, no, Why?
5. Can you see a reflected light directly? If, no Why?
1. You have observed your father handling the electric equipment by wearing glouses. Why?
2. If you connect a battery cell to the bulb through a wooden stick, the will not glow. Why?
3. Your father applies a tape over the joint of a electric wire. Why?
4. Do not handle the electric appliances when your hands are wet. Why?
5. There will be three colured wires normally used while connecting any electric equipment. What are those colours? Tell which coloured wire gives us electric shock?
1. When you are listening to song by using a small radio, it gives lot of disturbance when you changing the direction. Why?
2. If you want listen to a song by using a small radio by sitting in a rail compartment, you can’t Why?
3. While storing the magnets, a wooden stick is kept between the two magnets. Why?
4. Do not keep magnets near electronic equipment. Why?
5. Why a wooden piece can not made as a magnet?

Problem related to factorization,ratiolization

CBSE MATH STUDY: Problem related to factorization,ratiolization:Problem-1 If the values of a – b and ab are 6 and 40 respectively, find the values of a2 + b2 and (a + b)2.
Solution: a2 + b2 = (a – b)2 + 2ab = 62 + 2(40) = 36 + 80 = 116
(a + b)2 = (a – b)2 + 4ab = 62 + 4(40)= 36 + 160 = 196
Problem-2. If (x + p)(x + q) = x2 – 5x – 300, find the value of p2 + q2.
By product formula, we have (x + p) (x + q) = x2 + (p + q)x + pq.
So, by comparison, we get p + q = –5, pq = –300.
Now, we have p2 + q2 = (p + q)2 – 2 pq = (–5)2 –2(–300) = 25 + 600 = 625.
Problem-3. If (x + a)(x + b)(x + c) ≡ x3 – 6x2 + 11x – 6, find the value of a2 + b2+ c2.
Solution: From the product formula, we have
(x+a)(x+b)(x+c) = x3 + (a + b + c)x2 + (ab + bc + ca)x + abc.
Comparing, we get a + b + c = –6, ab + bc + ca = 11, abc = –6.
a2 + b2 + c2 = (a + b + c)2 –2 (ab + bc + ca) = (– 6)2 – 2(11) = 36 – 22 = 14.
Problem-4 If a+b=2 and a2+b2=8,find a3+b3 and a4+b4.

Friday, September 16, 2011

Revised syllabus in Tamil for classes IX and X for 2011-2012 onwards

CBSE also revised syllabus for classes IX and X for the academic year 2011-2012 onwards is as follows:

Syllabus already printed in Sec. curriculum vol II-2012 and 2013 may kindly be treated as cancelled.

1. Tamil syllabus- Class IX- Term I - April 2011 to September 2011 (onwards)
Max marks:90

(Detailed syllabus as per existing Exam structure. No change in Exam structure)


Thursday, September 15, 2011


Guess Questions 2012 Ch-9 FORCE AND LAWS OF MOTION...: 1. Which of the following statement is not correct for an object moving along a straight path in an accelerated motion? (a) Its speed keep...
For more downloadable guess paper



· Questions : 1 to 5 – 1 Mark each
· Questions : 6 to 9 – 2 Marks each
· Questions : 10 to 13 – 3 Marks each
· Question 14 – 5 Marks
1. Burning of a candle is a chemical change; where as melting of a candle wax is a chemical change. Why?




· Questions : 1 to 5 – 1 Mark each
· Questions : 6 to 9 – 2 Marks each
· Questions : 10 to 13 – 3 Marks each
· Question 14 – 5 Marks
1. On what chemical law, balancing of chemical equation is based?

Wednesday, September 14, 2011

Sample Papers & Study Materials for Class XI & XII 2011

1. Business Studies
2. Chemistry
3. Computer Science
4. Economics
5. History
Courtesy: KVS, RO, Hyderabad

Support Material on PSA, 2013-14
Support Material 2013-14 for Class XII